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Half-wormholes in nearly AdS2 holography
by Antonio M. García-García, Victor Godet
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Submission summary
Authors (as registered SciPost users): | Victor Godet |
Submission information | |
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Preprint Link: | scipost_202109_00031v2 (pdf) |
Date submitted: | 2022-01-15 07:51 |
Submitted by: | Godet, Victor |
Submitted to: | SciPost Physics |
Ontological classification | |
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Academic field: | Physics |
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Approaches: | Theoretical, Computational |
Abstract
We find half-wormhole solutions in Jackiw-Teitelboim gravity by allowing the geometry to end on a spacetime D-brane with specific boundary conditions. This theory also contains a Euclidean wormhole which leads to a factorization problem. We propose that half-wormholes provide a gravitational picture for how factorization is restored and show that the Euclidean wormhole emerges from averaging over the boundary conditions. The wormhole is known to be dual to a Sachdev-Ye-Kitaev (SYK) model with random complex couplings. We find that the free energy of the half-wormhole is strikingly similar to that of a single realization of this SYK model. These results suggest that the gravitational path integral computes an average over spacetime D-brane boundary conditions.
List of changes
minor changes detailed in the replies to the referees
Current status:
Reports on this Submission
Report #1 by Anonymous (Referee 3) on 2022-1-22 (Invited Report)
- Cite as: Anonymous, Report on arXiv:scipost_202109_00031v2, delivered 2022-01-22, doi: 10.21468/SciPost.Report.4220
Report
What I wanted to say is that z is an overall shift in the SYK definition of energy: for a generic tensor Jijkl, the sum ∑ijklJijklψiψkψkψl can be separated into two parts. The antisymmetric part of Jijkl gives the standard SYK hamiltonian.
The symmetric part of Jijkl yields a constant, since fermions anticommute: {ψi,ψj}=δij. Since all fermion operators disappear, the residual sum over ijkl yields z. This is a purely analytic argument. Interestingly, eq. (4.8) is indeed the shift in the ground state energy, after cancelling arctan and tan and factors of T. So one does not need to perform a numerical fit to obtain a precise relation between j0 and z(modulo subtleties of taking a log of a complex Z, presumably this is why you have arctan( tan) in eq. (4.8) ). I strongly believe that Section 6 should emphasize this point.
Author: Victor Godet on 2022-02-02 [id 2143]
(in reply to Report 1 on 2022-01-22)Thanks for your comment. I agree that z can be interpreted as a coupling-dependent ground state energy. I have modified the end of paragraph below 6.2 to reflect this, reproduced here:
The pattern in the imaginary part of F is indeed a consequence of the branch cut in the argument. This effect results from the fact that the partition is a sum of two exponentials, so we have schematically
Anonymous on 2022-02-06 [id 2161]
(in reply to Victor Godet on 2022-02-02 [id 2143])I thank Authors for the quick response. I recommend the paper for publication.