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Mapping a dissipative quantum spin chain onto a generalized Coulomb gas
by Oscar Bouverot-Dupuis
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Submission summary
Authors (as registered SciPost users): | Oscar Bouverot-Dupuis |
Submission information | |
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Preprint Link: | https://arxiv.org/abs/2403.06618v2 (pdf) |
Date submitted: | 2024-06-30 00:15 |
Submitted by: | Bouverot-Dupuis, Oscar |
Submitted to: | SciPost Physics |
Ontological classification | |
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Academic field: | Physics |
Specialties: |
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Approach: | Theoretical |
Abstract
An XXZ spin chain at zero magnetization is subject to spatially correlated baths acting as dissipation. We show that the low-energy excitations of this model are described by a dissipative sine-Gordon field theory, i.e. a sine-Gordon action with an additional long-range interaction emerging from dissipation. The field theory is then exactly mapped onto a generalized Coulomb gas which, in addition to the usual integer charges, displays half-integer charges that originate from the dissipative baths. These new charges come in pairs linked by a charge-independent logarithmic interaction. In the Coulomb gas picture, we identify a Berezinsky-Kosterlitz-Thouless-like phase transition corresponding to the binding of charges and derive the associated perturbative renormalization group equations. For superohmic baths, the transition is due to the binding of the integer charges, while for subohmic baths, it is due to the binding of the half-integer charges, thereby signaling a dissipation-induced transition.
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Author comments upon resubmission
I would like to thank both the referees for their valuable comments and appreciation of the results shown in the article. Following their suggestions and comments, I have edited certain parts of the manuscript. Below, I present a point-by-point response to all the queries of the referees.
Yours sincerely,
Oscar Bouverot-Dupuis
List of changes
"1- I am wondering about the decay of the dissipation kernel D(x,τ) in Eq. (14) and its dependence on the bath exponent s. For ν=0 it becomes D(x,τ)∝δ(x)/(τ/τc)2+s. In particular, for an ohmic bath with s=1 this leads to a retarded interaction that decays as 1/τ3. I always thought that an ohmic bath corresponds to a temporal decay ∝1/τ2, as it is also the case in Ref. [33] (a closely related paper by the author). It would be good to clarify this difference to the author's previous work (or correct it if it is a mistake)."
Answer : Thank you for pointing out this issue. The bath Kernel D(x,τ) is, roughly speaking, the Green's function of the bath operator G−1. For local baths, G−1 is the one dimensional operator G−11=−∂2τ+Ω2, while for non-local bath it is the two dimensional operator G−12=−v2∂2x−∂2τ+Ω2. It turns out that, as v is taken to 0, the Green's function G2 does not go to G1. This means that to study the v=0 case, one cannot directly set v=0 in the bath kernel D(x,τ) written in the article, but one has rather to rederive its expression from the microscopic model with v=0. With this in mind, local ohmic baths do indeed correspond to a temporal decay ∝1/τ2. Page 7 has been corrected accordingly and a footnote has also been added.
"2- On page 8 [below Eq. (20)], the author writes D(r−r). Isn't it just D(r)?"
3- First line on page 11 [above Eq. (24)]: The formatting of the in-line equation U=… is not clear because of the minus sign in front of Vc(r). Can one just put it in front of the integral?
4- On page 12 [the line below Eq. (27)]: I assume it is KR instead of Kr, right?"
Thanks for spotting these typos, they have been corrected.
Current status:
Reports on this Submission
Report #2 by Anonymous (Referee 2) on 2024-9-5 (Invited Report)
- Cite as: Anonymous, Report on arXiv:2403.06618v2, delivered 2024-09-05, doi: 10.21468/SciPost.Report.9712
Report
I thank the author for clarifying on page 7 that the $\nu\to0$ limit cannot be taken trivially from the derived equations. The author also discusses the implications of the $\nu\to0$ limit in Section 6. Because this discussion is rather technical, the meaning is not fully clear to me. As I understand this part, the Coulomb gas picture applies here as well, with the only difference that the interaction in Eq. (23) becomes local in space (and remains nonlocal in time). Is that correct?
In the introduction, the author reviews how the Coulomb-gas picture had been applied to generalized XY models, but I do not find any discussion of applications to dissipative systems. In the past, dissipation effects had also been studied in the context of Josephson junctions. For example, the Coulomb gas picture is mentioned for a single dissipative junction [Schmid, Phys. Rev. Lett. 51, 1506 (1983)] or for arrays of dissipative junctions [Bobbert, Fazio, Schön, Zimanyi, Phys. Rev. B 41, 4009 (1990)], but probably also in other works. It would be fair to review also relevant work including dissipation and to check if there are any similarities to the present work.
Recommendation
Ask for minor revision
Report #1 by Anonymous (Referee 1) on 2024-8-26 (Invited Report)
- Cite as: Anonymous, Report on arXiv:2403.06618v2, delivered 2024-08-26, doi: 10.21468/SciPost.Report.9655
Strengths
same as in previous report
Report
In my previous report, I had already recommended publication of the manuscript in SciPost. A few misprints numbered 2-4 were pointed out by the other referee and have been corrected in the revised version.
The second referee also raised the issue of the limit $\nu \to 0$ (point 1) and the authors have responded that the Green's function of the bath operator $(-\nu^2 \partial_x^2 -\partial_\tau^2+\Omega^2)^{-1}$ does not deform confinuously into the one on the local bath operator $(-\partial_\tau^{2} +\Omega^2)^{-1}$. They have also inserted a footnote in the manuscript making that argument.
I am not sure the argument of the authors is the correct one.
If we insert Eqs. (5) into Eq. (12) we find
\begin{eqnarray}
\label{eq:douze}
\mathcal{K}(x,\tau)=\frac{1}{\pi^2 \nu} \int_0^{\tau_c^{-1}} d\Omega \alpha \tau_c^{s-1} \Omega^{s+1} K_0\left(\Omega \sqrt{\tau^2 + (x/\nu)^2} \right)
\end{eqnarray}
If we let $\nu \to 0$ for $x\ne 0$, because of the exponential decay of the modified Bessel function for large argument, we obtain
\begin{equation}
\lim_{\nu \to 0} \mathcal{K}(x\ne 0,\tau) =0,
\end{equation}
while it is obvious that for $x=0$,
\begin{equation}
\lim_{\nu \to 0} \mathcal{K}(0,\tau) =+\infty.
\end{equation}
To verify that $\mathcal{K}(x,\tau)$ behaves as a Dirac delta distribution, we only need to calculate the weight
\begin{eqnarray}
\label{eq:weight}
\int dx \mathcal{K}(x,\tau) &=& \frac{1}{\pi^2} \int_0^{\tau_c^{-1}} d\Omega \alpha \tau_c^{s-1} \Omega^{s+1} \int_{-\infty}^{+\infty} K_0\left(\Omega \sqrt{\tau^2 + (x/\nu)^2} \right) \frac{dx}{\nu}, \\
&=& \frac{\alpha \tau_c^{s-1}}{\pi^2 \tau^{s+1}} \int_0^{\tau/\tau_c} dw w^{s+1} \int_{-\infty}^{+\infty} du K_0 (w \sqrt{1+u^2}),
\end{eqnarray}
and note that it is independent of $\nu$. Moreover, when $\tau \gg \tau_c$, we can extend the $w$ integration to $+\infty$ to find
\begin{eqnarray}
\label{eq:asymp-w}
\int dx \mathcal{K}(x,\tau\gg \tau_c) &\sim& \frac{\alpha \tau_c^{s-1}}{\pi^2 \tau^{s+1}} \int_{-\infty}^{+\infty} \frac{du}{(1+u^2)^{1+s/2}} \int_0^{+\infty} dv v^{s+1} K_0(v) \\
&\sim& \frac{\alpha \tau_c^{s-1}}{\pi^2 \tau^{s+1}} \\
&\sim& \frac{\alpha \tau_c^{s-1}\Gamma(s+1)}{\pi \tau^{s+1}},
\end{eqnarray}
and recover for $s=1$ the decay $1/\tau^2$ expected in an ohmic bath.
So even though the bath operators do not deform continuously into each other,
it is possible to recover the correct limit for $\nu \to 0$ directly from Eq. (12).
In other words, the comment 1 of the other referee was incorrect, and the authors
have been too cautious in their response and footnote.
I suggest the authors replace their footnote with a derivation of the delta distribution limit of the kernel from Eq. (12) and that final version of the manuscript gets published in SciPost.
Recommendation
Publish (easily meets expectations and criteria for this Journal; among top 50%)